Merge Sort
Merge Sort :
Author(s) : John von Neumann Date : 1945Merge sort is an efficient, general-purpose, and comparison-based sorting algorithm. Most implementations produce a stable sort, which means that the order of equal elements is the same in the input and output. Merge sort is a divide-and-conquer algorithm that was invented by John von Neumann in 1945.
| Time Complexity | O(n log n) |
| Best Case | O(n log n) |
| Worst Case | O(n log n) |
| Space Complexity | O(n) |
| Stable | Yes |
Code Integration:
* the code might contain some bugs or may not work correctly
def merge_sort(arr):
if len(arr) > 1:
mid = len(arr) // 2
L = arr[:mid]
R = arr[mid:]
merge_sort(L)
merge_sort(R)
i = j = k = 0
while i < len(L) and j < len(R):
if L[i] <= R[j]:
arr[k] = L[i]
i += 1
else:
arr[k] = R[j]
j += 1
k += 1
while i < len(L):
arr[k] = L[i]
i += 1
k += 1
while j < len(R):
arr[k] = R[j]
j += 1
k += 1
function mergeSort(arr) {
if (arr.length <= 1) return arr;
const mid = Math.floor(arr.length / 2);
const left = mergeSort(arr.slice(0, mid));
const right = mergeSort(arr.slice(mid));
let i = 0, j = 0, k = 0;
while (i < left.length && j < right.length) {
if (left[i] <= right[j]) {
arr[k++] = left[i++];
} else {
arr[k++] = right[j++];
}
}
while (i < left.length) arr[k++] = left[i++];
while (j < right.length) arr[k++] = right[j++];
return arr;
}
public static void mergeSort(int[] arr, int l, int r) {
if (l < r) {
int m = l + (r - l) / 2;
mergeSort(arr, l, m);
mergeSort(arr, m + 1, r);
merge(arr, l, m, r);
}
}
private static void merge(int[] arr, int l, int m, int r) {
int n1 = m - l + 1;
int n2 = r - m;
int[] L = new int[n1];
int[] R = new int[n2];
for (int i = 0; i < n1; ++i) L[i] = arr[l + i];
for (int j = 0; j < n2; ++j) R[j] = arr[m + 1 + j];
int i = 0, j = 0, k = l;
while (i < n1 && j < n2) {
if (L[i] <= R[j]) {
arr[k] = L[i];
i++;
} else {
arr[k] = R[j];
j++;
}
k++;
}
while (i < n1) {
arr[k] = L[i];
i++;
k++;
}
while (j < n2) {
arr[k] = R[j];
j++;
k++;
}
}
func mergeSort(arr []int) []int {
if len(arr) <= 1 {
return arr
}
mid := len(arr) / 2
left := mergeSort(arr[:mid])
right := mergeSort(arr[mid:])
return merge(left, right)
}
func merge(left, right []int) []int {
res := make([]int, 0, len(left)+len(right))
i, j := 0, 0
for i < len(left) && j < len(right) {
if left[i] <= right[j] {
res = append(res, left[i])
i++
} else {
res = append(res, right[j])
j++
}
}
res = append(res, left[i:]...)
res = append(res, right[j:]...)
return res
}
void merge(int arr[], int l, int m, int r) {
int i, j, k;
int n1 = m - l + 1;
int n2 = r - m;
int L[n1], R[n2];
for (i = 0; i < n1; i++) L[i] = arr[l + i];
for (j = 0; j < n2; j++) R[j] = arr[m + 1 + j];
i = 0; j = 0; k = l;
while (i < n1 && j < n2) {
if (L[i] <= R[j]) {
arr[k] = L[i];
i++;
} else {
arr[k] = R[j];
j++;
}
k++;
}
while (i < n1) {
arr[k] = L[i];
i++;
k++;
}
while (j < n2) {
arr[k] = R[j];
j++;
k++;
}
}
void mergeSort(int arr[], int l, int r) {
if (l < r) {
int m = l + (r - l) / 2;
mergeSort(arr, l, m);
mergeSort(arr, m + 1, r);
merge(arr, l, m, r);
}
}